Question: 2. 3 - 16 O = tan -1 : 63.43 3 (262+62)=6.7 P =vi Polar Form: 6.7263.430 3. 15 + j25 O =tan -1 25

2. 3 - 16 O = tan -1 : 63.43 3 (262+62)=6.7 P =vi
2. 3 - 16 O = tan -1 : 63.43 3 (262+62)=6.7 P =vi Polar Form: 6.7263.430 3. 15 + j25 O =tan -1 25 =59.03 15 15 (642+253)=29.15 P =Vt Polar Form: 29.15259.03 4. 24 + j30 -1 30 O =tan =51.34 24 24 (642+30')=38.42 P=vt

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