$2\mathrm{.}50*$ CALC A small object moves along the $x-$axis with acceleration $a_x(t)=-(0\mathrm{.}0320\frac{m}{s^3})(15\mathrm{.}0s-t).$ At $t=0$ the object is at $x=-14\mathrm{.}0m$ and has velocity $v_{0_r}=8\mathrm{.}00\frac{m}{s}.$ What is the $x-$coordinate of the object when $t=10\mathrm{.}0s?$