Question: 2. A charge q = -2.5 nC is initially a distance r = 5.7 cm away from a stationary charge q2 = +3.1nC. (a)

2. A charge q = -2.5 nC is initially a distance r = 5.7 cm away from a stationary charge q2 = +3.1nC. (a) What is the electric potential of q (from 92) at its initial position (if zero potential is infinitely far away)? (b) The charge q then falls toward the stationary charge and is stopped a distance r = 1.2 cm away from q2. What is the change in potential AV? (c) What is the work that the electric field from q2 performs on q as the latter charge transits from to r? An external agent then moves q from r to a distance r3 = 10.5 cm away from q2. (d) What is the change in potential from 12 to 13? (e) What is the work the agent must supply? For all parts, be careful regarding the signs!

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