Question: 2. A juggler performs in a room whose ceiling is 3.00 m above the level of his hands. He throws a ball upward so

2. A juggler performs in a room whose ceiling is 3.00 m

2. A juggler performs in a room whose ceiling is 3.00 m above the level of his hands. He throws a ball upward so that it just reaches the ceiling. (a) What is the initial velocity of the ball? (b)What is the time required for the ball to reach the ceiling? At the instant when the first ball is at ceiling, the juggler throws a second ball upward with two-thirds the initial velocity. (c) How long after the second ball is thrown did the two balls pass each other? (d) At what distance above the juggler's hand do they pass each other?

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To solve this problem well use the equations of motion under constant acceleration due to gravity Lets denote the initial velocity as v0 the final velocity as v the acceleration due to gravity as g 98 ... View full answer

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