2. A rigid vessel of diameter 0.5 m contains 0.92 kg of air at 720 K...

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2. A rigid vessel of diameter 0.5 m contains 0.92 kg of air at 720 K and 3 bars. Considering the air to behave as an ideal gas R=287 a. Determine the specific volume of the gas and the volume of the vessel. mRT 0.92x287x720 3x105 volume gas = pV = mRT V = - P = 0.634kgm = 0.689m kg- RT 287x720 volume vessel = pv = RT v = = = P 3x105 b. Some of the air is vented isothermally to an empty cylinder of diameter 0.4 m which has a 900kg mass on the piston as shown in Figure Q1. If the piston rises to a height of 0.3 m, determine the mass of gas in the cylinder. Rigid vessel Mass, 900 kg Piston Figure Q1 Note: we are assuming here, that the pressure is maintained in the cylinder due to the mass. c.A valve isolates the cylinder from the rigid vessel and 20 kJ of heat is added to the cylinder. Calculate the new volume of the cylinder and the work done firstly as an isobaric process and isothermal processes. Taking Cp=1.02 kJkg K and C=0.718 kJkg"K. d. 20 kJ of heat is now added to the rigid tank. What is the new temperature? 2. A rigid vessel of diameter 0.5 m contains 0.92 kg of air at 720 K and 3 bars. Considering the air to behave as an ideal gas R=287 a. Determine the specific volume of the gas and the volume of the vessel. mRT 0.92x287x720 3x105 volume gas = pV = mRT V = - P = 0.634kgm = 0.689m kg- RT 287x720 volume vessel = pv = RT v = = = P 3x105 b. Some of the air is vented isothermally to an empty cylinder of diameter 0.4 m which has a 900kg mass on the piston as shown in Figure Q1. If the piston rises to a height of 0.3 m, determine the mass of gas in the cylinder. Rigid vessel Mass, 900 kg Piston Figure Q1 Note: we are assuming here, that the pressure is maintained in the cylinder due to the mass. c.A valve isolates the cylinder from the rigid vessel and 20 kJ of heat is added to the cylinder. Calculate the new volume of the cylinder and the work done firstly as an isobaric process and isothermal processes. Taking Cp=1.02 kJkg K and C=0.718 kJkg"K. d. 20 kJ of heat is now added to the rigid tank. What is the new temperature?

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The question presents a multipart physics problem involving a gas within a rigid vessel and an adjacent cylinder Lets address each part methodically Part b For part b we are given that some of the air ... View the full answer