Lab 5: Equilibrium Data Standard Solutions Molar concentration of Fe(NO3)3 0.200 M Molar concentration of NaSCN...
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Lab 5: Equilibrium Data Standard Solutions Molar concentration of Fe(NO3)3 0.200 M Molar concentration of NaSCN 0.0010 M Table 1. Standard Solutions Solution 0.200 M Fe(NO3)3 10 ml 10 ml 10 ml 10 ml Blank 1 2 3 4 5 Solution Blank 6 10 ml 10 ml 7 8 Volume, mL 0.0010 M NaSCN 0 1.0 2.0 3.0 4.0 5.0 9 10 Calibration curve: Plot absorbance versus [FeSCN*2] Test Solutions Molar concentration of Fe(NO3)3 0.002 M Molar concentration of NaSCN 0.002 M Table 2. Test Solutions 0.1 M HNO3 0.002 M Fe(NO3)3 5.0 5.0 5.0 5.0 5.0 5.0 Data Analysis 15.0 0 0 14.0 0.000001 0.00004 13.0 0.000002 0.00008 12.0 0.000003 0.00014 Moles NaSC 11.0 0.000004 0.00016 1.35e-4 10.0 0.000005 0.0002 1.56e-4 Volume, mL 0.002 M NaSCN 0 1.0 2.0 3.0 4.0 5.0 [NaSCN] [FeSCN*2] Absorbance mol/L mol/L at 447 nm 0.1 M HNO3 5.0 4.0 3.0 2.0 1.0 0 0 4.02e-5 6.09e-5 1.21e-4 Initial # mole Fe+3 0.001 0.001 0.001 0.001 0.001 0.001 SCN 0 0.0002 0.0004 0.0006 0.0008 0.001 0 0.177 0.268 0.535 0.595 0.689 Absorbance at 447 nm 0 0.207 0.335 0.421 0.473 0.512 Table 3: Equilibrium Conditions Solution 6 7 8 9 10 Solution 6 7 8 9 10 [FeSCN¹21" mol/L [FeSCN*2]** mol/L Iron Equilibrium Moles Moles Fe*3 FeSCN¹2 reacted Using the equation K = Solution 6 Keq = Solution 7 Keq = Solution 8 Keq= Solution 9 Keq = Solution 10 Keq = Ave Keq = [FeSCN+2] eq [Fe +³[SCN] Moles Fe*3 unreacted [Fe*3] unreacted, mol/L Thiocyanate Equilibrium Moles Moles SCN Moles SCN [SCN] unreacted, SCN reacted unreacted mol/L calculate the equilibrium constant for solution 6 below: Lab 5: Equilibrium Data Standard Solutions Molar concentration of Fe(NO3)3 0.200 M Molar concentration of NaSCN 0.0010 M Table 1. Standard Solutions Solution 0.200 M Fe(NO3)3 10 ml 10 ml 10 ml 10 ml Blank 1 2 3 4 5 Solution Blank 6 10 ml 10 ml 7 8 Volume, mL 0.0010 M NaSCN 0 1.0 2.0 3.0 4.0 5.0 9 10 Calibration curve: Plot absorbance versus [FeSCN*2] Test Solutions Molar concentration of Fe(NO3)3 0.002 M Molar concentration of NaSCN 0.002 M Table 2. Test Solutions 0.1 M HNO3 0.002 M Fe(NO3)3 5.0 5.0 5.0 5.0 5.0 5.0 Data Analysis 15.0 0 0 14.0 0.000001 0.00004 13.0 0.000002 0.00008 12.0 0.000003 0.00014 Moles NaSC 11.0 0.000004 0.00016 1.35e-4 10.0 0.000005 0.0002 1.56e-4 Volume, mL 0.002 M NaSCN 0 1.0 2.0 3.0 4.0 5.0 [NaSCN] [FeSCN*2] Absorbance mol/L mol/L at 447 nm 0.1 M HNO3 5.0 4.0 3.0 2.0 1.0 0 0 4.02e-5 6.09e-5 1.21e-4 Initial # mole Fe+3 0.001 0.001 0.001 0.001 0.001 0.001 SCN 0 0.0002 0.0004 0.0006 0.0008 0.001 0 0.177 0.268 0.535 0.595 0.689 Absorbance at 447 nm 0 0.207 0.335 0.421 0.473 0.512 Table 3: Equilibrium Conditions Solution 6 7 8 9 10 Solution 6 7 8 9 10 [FeSCN¹21" mol/L [FeSCN*2]** mol/L Iron Equilibrium Moles Moles Fe*3 FeSCN¹2 reacted Using the equation K = Solution 6 Keq = Solution 7 Keq = Solution 8 Keq= Solution 9 Keq = Solution 10 Keq = Ave Keq = [FeSCN+2] eq [Fe +³[SCN] Moles Fe*3 unreacted [Fe*3] unreacted, mol/L Thiocyanate Equilibrium Moles Moles SCN Moles SCN [SCN] unreacted, SCN reacted unreacted mol/L calculate the equilibrium constant for solution 6 below:
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Solution Since So Solution 1 2 345 02 M fet3 10 Solution 1 Nasen is ... View the full answer
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Financial Reporting and Analysis Using Financial Accounting Information
ISBN: 978-1439080603
12th Edition
Authors: Charles H Gibson
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