Question: 2) Consider a binary classifier with inputs x1 and x2 and output y as follows: x(1)=[12]y(1)=1x(2)=[.50]y(2)=0x(3)=[0.5]y(3)=1m=3,nx=2 Initial conditions: w=[00],b=0,J=0 =0.1 Here is the vectovized back
![output y as follows: x(1)=[12]y(1)=1x(2)=[.50]y(2)=0x(3)=[0.5]y(3)=1m=3,nx=2 Initial conditions: w=[00],b=0,J=0 =0.1 Here is the](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f4ddfb865d1_64266f4ddfaeddd0.jpg)
![vectovized back progagation al gorithm? for i in range (epodh): ZAdZddb:=b:=LJ=X+b=npdot(TX)+b=(z)=AY=m1XdZT=m1npsun(dz)dbdb=[ylog(A)+(1y)log(1A)]=m1npsom(L) Now,](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f4ddfc6940c_64366f4ddfbd3760.jpg)
2) Consider a binary classifier with inputs x1 and x2 and output y as follows: x(1)=[12]y(1)=1x(2)=[.50]y(2)=0x(3)=[0.5]y(3)=1m=3,nx=2 Initial conditions: w=[00],b=0,J=0 =0.1 Here is the vectovized back progagation al gorithm? for i in range (epodh): ZAdZddb:=b:=LJ=X+b=npdot(TX)+b=(z)=AY=m1XdZT=m1npsun(dz)dbdb=[ylog(A)+(1y)log(1A)]=m1npsom(L) Now, by hand calculate the vaviables for the 2ud and 3rd iteration. The 1st iteration is done for you below. Now, by hand calculate the variablCs for the 20ade zrd iteration. The ist iteration is done for you belou. ic 155 2) Consider a binary classifier with inputs x1 and x2 and output y as follows: x(1)=[12]y(1)=1x(2)=[.50]y(2)=0x(3)=[0.5]y(3)=1m=3,nx=2 Initial conditions: w=[00],b=0,J=0 =0.1 Here is the vectovized back progagation al gorithm? for i in range (epodh): ZAdZddb:=b:=LJ=X+b=npdot(TX)+b=(z)=AY=m1XdZT=m1npsun(dz)dbdb=[ylog(A)+(1y)log(1A)]=m1npsom(L) Now, by hand calculate the vaviables for the 2ud and 3rd iteration. The 1st iteration is done for you below. Now, by hand calculate the variablCs for the 20ade zrd iteration. The ist iteration is done for you belou. ic 155
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