Question: 2. During smog events, NO2 is simultaneously consumed by the following reactions: k1 NO2 ----> NO + O at 2pm: k1 = 8 x 10-3

2. During smog events, NO2 is simultaneously consumed by the following reactions: k1 NO2 ----> NO + O at 2pm: k1 = 8 x 10-3 s-1 at 7pm: k1 = 8 x 10-4 s-1 k2 NO2 + OH ----> HNO3 k2 = 1.1 x 10-11 cm3 molecule-1 s-1

Briefly explain which reaction (1 or 2) consumes more NO2 at 2pm and 7pm.

I used the equation [NO2]K1/[NO2]*OH*K2. The NO2s cancel for 2pm and 7pm. I plug in the given numbers and get 8*10^-3/1.1*10^-4 and 8*10^-4/1.1*10^-4 and both the reaction 1 the k1 reactions consume more NO2 at both 2 and 7 pm. Is this correct?

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