Question: 2. Force = 12 N is exerted on a particle at position 7 = (13 32) m. a) What is the torque on the

2. Force = 12 N is exerted on a particle at position

2. Force = 12 N is exerted on a particle at position 7 = (13 32) m. a) What is the torque on the particle about the origin. (10 points, out of which 1 point is for the equation being used, 5 points are for showing all the calculations using the determinant method, with the determinant written out and labeled, and 1 point is for writing the answer to three significant figures with the direction, and units). b) If the particle has a mass of 0.71 kg, and its radius of rotation is r = 33.4 m, what is the angular acceleration (a) of the particle due to this torque? (5 points, out which 2 points are for equations used and their names, and 1 point is for writing the answer in decimal form to three significant figures, with the units). Hint: the moment of inertia of this particle is / = mr kg m. write out your detailed solution with an explanation to each step. 2. Force = 12 N is exerted on a particle at position 7 = (13 32) m. a) What is the torque on the particle about the origin. (10 points, out of which 1 point is for the equation being used, 5 points are for showing all the calculations using the determinant method, with the determinant written out and labeled, and 1 point is for writing the answer to three significant figures with the direction, and units). b) If the particle has a mass of 0.71 kg, and its radius of rotation is r = 33.4 m, what is the angular acceleration (a) of the particle due to this torque? (5 points, out which 2 points are for equations used and their names, and 1 point is for writing the answer in decimal form to three significant figures, with the units). Hint: the moment of inertia of this particle is /= mr kg m. write out your detailed solution with an explanation to each step.

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a To find the torque on the particle about the origin Given 00 F 12 i N 7 13 32 Y XF Op We wi... View full answer

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