Question: 2. Given a function over positive integers, where F(0)=0; and F(n)=1+F(floor(n/2)). Then show that F(n)=1+floor(log2(n)). Here floor(n/2)=(n-1)/2 if n is odd and n/2 if n

2. Given a function over positive integers, where F(0)=0; and F(n)=1+F(floor(n/2)). Then show that F(n)=1+floor(log2(n)). Here floor(n/2)=(n-1)/2 if n is odd and n/2 if n is even. (5 points)

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