Question: 2. Let p(x) = x3 - 5x +1. (a) Show that p(x) has (at least) a root in the interval [0, 1]. (Hint: Use the

 2. Let p(x) = x3 - 5x +1. (a) Show that

p(x) has (at least) a root in the interval [0, 1]. (Hint:

2. Let p(x) = x3 - 5x +1. (a) Show that p(x) has (at least) a root in the interval [0, 1]. (Hint: Use the intermediate value theorem) (b) Is this root closer to 0 or closer to 1? (in other words, does it belongs to [0, 1/2] or [1/2, 1]?)

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