Question: 2. We have been using A = (2ar)Ar as the cross-sectional area of an anulus. a. Prove that the actual area is A = (2#r)Ar

 2. We have been using A = (2ar)Ar as the cross-sectional

2. We have been using A = (2ar)Ar as the cross-sectional area of an anulus. a. Prove that the actual area is A = (2#r)Ar + RAM O C b. Would using the correct area still yield the differential equation: d dr PL-P ul dr On the next page, perform the derivation to prove your assertion

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