Question: 20 1point ... Q20 1 Point The absolute maximum value of f (x) = x3 - 6x2 + 5 on the closed interval -1, 5

20 1point ...

20 1point ... Q20 1 Point The absolute maximum value of f

Q20 1 Point The absolute maximum value of f (x) = x3 - 6x2 + 5 on the closed interval -1, 5 occurs at T - a. Determine a. Oa = -1 Qa =0 Oa =2 Oa = 4 Oa = 5

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