According to the function x2 4x + 1 shown, which statement provides a true conclusion? The function f(x) is not continuous on a closed interval (0, 3) and, therefore, x) has neither a maximum nor a minimum value on [0. 3]. O The function f(x) is continuous on a closed interval [0, 3] and, therefore, x) has both a maximum and minimum value on [I]. 3]. The function f(x) is not continuous on a closed interval [0, 3] and, therefore, f(x) has both a maximum and minimum value on [0. 3]. The function f(x) is continuous on a closed interval (0, 3) and, therefore, f(x) has either a maximum or a minimum value on [0. 3]. According to the functionf (x) = 2x4 4x2 + 6 shown, which statement provides a true conclusion? The function x) is continuous on a closed interval [-1, 1] and, therefore, x) has either a maximum or minimum value on O [-1. 1]. C" The function x) is continuous on a closed interval [-1, 1] and, therefore. x) has both a maximum and minimum value on " [-1. 1]. O The function x) is not continuous on a closed interval [-1, 1] and. therefore. x) has both a maximum and minimum value on [-1. 1]. O The function x) is not continuous on a closed interval [-1, 1] and. therefore. x) has neither a maximum nor a minimum value on [-1. 1]. Find the maximum value effLI) = I2 3x + 2 in the interval [0, 5]. C73 The absolute maximum value is _T1 at): = % G The absolute maximum value is U at x = 2. Q The absolute maximum value is 2 at x = i]. G The absolute maximum value is 12 at x = 5. Find the maximum value of nix} = 2x2 5 x + 2in the interval [-2, 2]. Ci The absolute maximum value is U at x = 2. 5 U The absolute maximum value is % at I = E . O The absolute maximum value is 20 at x = -2. U The abaelute maximum value is 20 at x = 2. Find the minimum value of fix} = 2x2 5 x + 2 in the interval [-2, 2]. O The absolute minimum value is 2 at x = D U The absolute minimum value is % at I = % Q The absolute minimum value is D at x = 2. 3 The absolute minimum value is 20 at = -2. Find the maximum value eff(.1') = x2 x 4in the interval [-3, 3]. C] The abaelute maximum value is -10 at x = -3. Ci The absolute maximum value is 46 at x = 3. U The abaelute maximum value is -4 at x = U. C] The absolute maximum value is g at Ji? = 21 . Find the minimum value of f(x) = x2 x 4in the interval [-3. 3]. C1 The absolute minimum value is -4 at x = l]. CI The absolute minimum value is g at x = % O The absolute minimum value is -1E'i at x = 3. O The absolute minimum value is -10 at x = -3. Find the maximum value of f (x) = 6x2 + 7x 24 in the interval [-2, 1]. G The absolute maximum value is 44 at x = -2. O The absolute maximum value is -2 at x = % . O The absolute maximum value is -11 at x = 1. 625 i O The absolute maxlmum value ls E at .17 12 Find the minimum value of x} = cos x in the interval [JT, II] . C1 The absolute minimum value is 1 at x = D. U The absolute minimum value is -1 at x = -n and -1 at x = n O The absolute minimum value is -1 at x = II {J The absolute minimum value is -1 at x = -n