(20%) Problem 3: A 2700 kg car is driving down a highway at a constant velocity when a deer jumps out onto the road 79.5 m ahead. The coefcient of friction between the car tires and the road is 0.33 . Q Calculate the initial velocity of the car if it is able to stop just before hitting the deer. (You do not need to account for reaction time of the driver. Assuming the car is breaking the entire 79.5 m distance and that friction is the only force stopping the car.) Grade Summary V0 = I Ill/S Deductions Potential 100' (20%) Problem 2: A 40 N box is resting on a table when a 10 N force is applied to it horizontally. The coefcients of static and kinetic friction are 0.3 and 0.1 , respectively. & Which of the following best describes the resulting motion of the box? . Grade Summary 0 The box remains at rest. - - . Deductions O The box accelerates 1n the direction of the applied force. Potential 100% O The motion of the box cannot be determined with the given information. Submissions 0 The box moves with a constant velocity in the direction of the applied force. Attempts remaining: (_ per attempt) Ancnuna mm\(20%) Problem 4: In the diagram shown, mass 1 (m1) is 12.12 kg and the coefficients of static and kinetic friction are 0.25 and 0.13, respectively. Shah, Isha - shahis 17 @students.rowan.edu m1 m2 - What is the required mass for mass 2 (m2) so mj moves with a constant velocity? Assume that the pulley shown is ideal, massless, and frictionless. Grade Summary m2 = kg Deductions 0% Potential 100% sin() cos() tan() 7 8 9 HOME Submissions Attempts remaining: 4 cotan() asin() acos() pi A 4 5 6 (0% per attempt) detailed view atan() acotan() sinh() 2 3 cosh() tanh() cotanh() + 0 END ODegrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up!(20%) Problem 5: A steel column is a cylinder 5.6 m long and 0.35 m in diameter. Shah, Isha - shahis 17@students.rowan.edu What is the change in length of the column when it experiences a tensile stress resulting from the application of a 3100 N force? The elastic modulus for steel is 20 x 1010 Nm2/kg2. Grade Summary AL = 1 m Deductions 0% Potential 100% sin() cos tan() 7 8 9 HOME Submissions Attempts remaining: 4 cotan() asin() acos() E TA A 5 6 (0% per attempt) detailed view atan() acotan() sinh() 2 3 cosh() tanh() cotanh() + 0 END O Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: Feedback