>25% Part (a) Suppose that numeric values are chosen such that the block comes to rest before reaching the bottom of the ramp. Let a be the distance traveled from the equilibrium position of the block towards the bottom of the ramp. Enter an expression for x. x=(-k Ax)/(2 mg (sin(e) - cos(0))) - Ax Correct! A 25% Part (b) Suppose that the block has mass m = 2.6 kg, the angle of the plane with the horizontal is 0 = 41, the coefficient of friction between the block and the inclined plane is = 0.24, the height of the block when the spring is at its equilibrium length is h = 0.67 m. the spring constant is k = 24 N/m, and the initial compression of the spring is Ax = 0.19 m. With these values, the block will reach the bottom of the ramp.. Find the speed, in meters per second, of the block when it reaches the end of the ramp. Treat the block as a point. A 25% Part (c) Once the block reaches the bottom, it encounters a new coefficient of friction, 2 = 0.105. What distance, a, in meters, could the block travel on this surface before stopping if no obstacles were in the way? Assume the size of the block is negligible and that it transitions smoothly from the ramp to the horizontal plane. A 25% Part (d) The block travels a distance d = 0.18 m along the surface with friction coefficient 2 = 0.105. The horizontal surface then becomes frictionless, at the equilibrium position of a spring with constant 2 = 5.9 N/m. Calculate the distance. As, in meters, by which the spring is compressed as the block comes to rest. select part As = m sin() cotan() cos tan ( ) 7 8 9 HOME asin() acos() EM4 5 6 atan() acotan() cosh() tanh() cotanh() Degrees Radians sinh() * 1 2 3 + - 0 END VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up!