2.Needing help to correct this practice question.

(g) Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places.) Confidence interval 6.37 12.63A study compared three display panels used by air trafc controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panelemergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition Display Panel 1 2 3 4 A 17 25 31 14 14 24 34 13 B 15 22 28 9 12 19 31 10 C 21 29 32 15 24 28 37 19 Least Squares Means Estimates Panel Estimate Condition Estimate A 21.500000 1 17.166667 B 18.250000 2 24.500000 C 25.625000 3 32.166667 4 13.333333 Analysis of Variance Sum of Mean Source DE Squares Square F Ratio Model 11 1482.4583 134.769 32.6713 Error 12 49.5000 4.125 Prob > F C. Total 23 1531.9583 <.0001 effect tests sum of source nparm. df squares f ratio prob> F Panel 2 2 218.5833 26.4949 <.0001 condition pane1 tukey hsd all pain comparisons guantile="2.66776," adjusted df="12.0," adjustment="Tukey" panel difference std error t ratio prob>|t| Lower 95% Upper 95% A B 3.25000 1.015505 3.20 0.0194* 0.5409 5.95912 A C 4.12500 1.015505 4.06 0.0042* 6.8341 1.41588 B C 7.37500 1.015505 -7.26 | t/ Lower 95% Upper 95% 1 -7.3333 1. 172604 -6.25 0 . 0002* -10 . 8146 -3 . 8521 -15 . 0000 1. 172604 -12 . 79