3 2 2 points u-substitution must be used to find the general antiderivative of the following:...

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3 2 2 points u-substitution must be used to find the general antiderivative of the following: x5 Vx - 8.5x dx (2.) Find du in terms of x and dx. 1 du (x5-8). 5x dx 2 du du = x5 x5 - 8.20x dx + (x5 - 8). 5x dx du = 20x dx = du = 5x+dx 2 points u-substitution must be used to find the general antiderivative of the following: 5 - 8.5x dx (3.) Substitute to get an integral in terms of u and du. O u. 52 dr 5 x 8 udu X 1 (u) + 5x dr 2 2udu 2udu 3 2 2 points u-substitution must be used to find the general antiderivative of the following: x5 Vx - 8.5x dx (2.) Find du in terms of x and dx. 1 du (x5-8). 5x dx 2 du du = x5 x5 - 8.20x dx + (x5 - 8). 5x dx du = 20x dx = du = 5x+dx 2 points u-substitution must be used to find the general antiderivative of the following: 5 - 8.5x dx (3.) Substitute to get an integral in terms of u and du. O u. 52 dr 5 x 8 udu X 1 (u) + 5x dr 2 2udu 2udu