Question: 3. (20 points) In the following two programs, the executable program /bin/prog does not print anything, and printf() always prints immediately i.e., there is no

3. (20 points) In the following two programs, the executable program "/bin/prog" does not print anything, and printf() always prints immediately i.e., there is no I/O buffering). int main(int arge, char +argv[]) { // prog-1 int rc = fork(); if (rc == 0) { printf("1"); } else if (rc > 0) { wait (NULL); printf("2"); } else { printf("3"); return 0; (1) If the calls to fork () and wait() always succeed, list all the possible outputs of the above program i.e., prog-1). (2) If the calls to fork () and wait () might fail, list all the possible outputs of the above program (i.e., prog-1) and explain how each of the outputs may happen. int main(int argc, char *argv[]) { // prog-2 int rc = fork(); if (rc == 0) { char *argv[] = { "/bin/prog", NULL); execv(argv[0], argv); printf("1"); } else if (rc > 0) { printf("2"); printf("3"); return 0; (3) If the calls to fork () and execv() always succeed, list all the possible outputs of the above program i.e., prog-2). (4) If the calls to fork () and execv() might succeed, list all the possible outputs of the above program i.e., prog-2) and explain how each of the outputs may happen. 3. (20 points) In the following two programs, the executable program "/bin/prog" does not print anything, and printf() always prints immediately i.e., there is no I/O buffering). int main(int arge, char +argv[]) { // prog-1 int rc = fork(); if (rc == 0) { printf("1"); } else if (rc > 0) { wait (NULL); printf("2"); } else { printf("3"); return 0; (1) If the calls to fork () and wait() always succeed, list all the possible outputs of the above program i.e., prog-1). (2) If the calls to fork () and wait () might fail, list all the possible outputs of the above program (i.e., prog-1) and explain how each of the outputs may happen. int main(int argc, char *argv[]) { // prog-2 int rc = fork(); if (rc == 0) { char *argv[] = { "/bin/prog", NULL); execv(argv[0], argv); printf("1"); } else if (rc > 0) { printf("2"); printf("3"); return 0; (3) If the calls to fork () and execv() always succeed, list all the possible outputs of the above program i.e., prog-2). (4) If the calls to fork () and execv() might succeed, list all the possible outputs of the above program i.e., prog-2) and explain how each of the outputs may happen
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