$3\mathrm{.}3\mathrm{.}6-$kip load shown. The internal pressure in the pipe is $380$ psi. Assume a$=28$in$.,$b$=46$ in$.,$ P$=3\mathrm{.}6$ kips, and $\backslash$beta $=43\backslash$deg y$-$z plan so that there is a y and z component to the force, but not x componentK and the total shear stress and represent this stress state on a stress element. $\backslash$sigma $\_($x$)=-9\mathrm{.}73$ksi,$\backslash$sigma v$=10\mathrm{.}6$ksi,$\backslash$tau $\_($xy$)=-13\mathrm{.}3$ksi.