Question: 3. (4 pts) Given g(x) = =x3 - 2x2 + 3x - 4, find the absolute extreme values of g(x) on the interval [-2,2] using

3. (4 pts) Given g(x) = =x3 - 2x2 + 3x - 4, find the absolute extreme values of g(x) on the interval [-2,2] using our calculus techniques (not just looking at a graph!). 4. (4 pts) Sketch a continuous graph with the following properties. Be as precise as you can to properly show increasing/decreasing, local extrema, concavity, and points of inflection. f' (x) > 0 when - 4 2 f' (-4) = 0 and f' (0) = 0 . f' (2) = DNE f"(x) > 0 when x 2 . f"(x)

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