$(35\%),$ Water initially occupies the left side of the rigid box shown below. It is

separated from a vacuum on the other side by a movable sliding partition. The $1\mathrm{.}2$ lb m of water

is initially at a temperature of $400F$ and pressure of $200$ psia $($State $1).$ In the first of two steps,

the slide is withdrawn and the water moves to occupy the entire box in an adiabatic process

where the pressure after, at State $2,$ is $140$ psia. In the second step there is heat transfer to the

surroundings, leaving the water with a final temperature $($State $3)$ of $250F.$ Find:

a$)$ The volume of the box on the left side of the partition $(f{t}^3).$

b$)$ The temperature at State $2(F).$

c$)$ The total volume of the box $(f{t}^3).$

d$)$ The final pressure at State $3($psia$)$

e$)$ The heat transfer for step $2($Btu$)$

$m_1=1\mathrm{.}21cm$

$T_1=40.F=859\mathrm{.}60n$

$P_1=2c\frac{e}{s}ic$