3. A 4 to 2 priority encoder has four inputs Y3, Y2, Y1 & YO and...

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3. A 4 to 2 priority encoder has four inputs Y3, Y2, Y1 & YO and two outputs A1 & A0. The input Y3 has the highest priority, whereas the input, YO has the lowest priority. In this case, even if more than one input is '1' at the same time, the output will be the binary code corresponding to the input, which is having higher priority. (25 pts) We will consider one more output, V in order to know, whether the code available at outputs is valid or not. - If at least one input of the encoder is '1', then the code available at outputs is a valid one. In this case, the output, V will be equal to 1. If all the inputs of encoder are '0', then the code available at outputs is not a valid one. In this case, the output, V will be equal to 0 A. Generate the truth table. B. Using K-map or Boolean algebra, determine the logical expression for outputs. C. Draw the circuit diagram of the outputs in step b. 3. A 4 to 2 priority encoder has four inputs Y3, Y2, Y1 & YO and two outputs A1 & A0. The input Y3 has the highest priority, whereas the input, YO has the lowest priority. In this case, even if more than one input is '1' at the same time, the output will be the binary code corresponding to the input, which is having higher priority. (25 pts) We will consider one more output, V in order to know, whether the code available at outputs is valid or not. - If at least one input of the encoder is '1', then the code available at outputs is a valid one. In this case, the output, V will be equal to 1. If all the inputs of encoder are '0', then the code available at outputs is not a valid one. In this case, the output, V will be equal to 0 A. Generate the truth table. B. Using K-map or Boolean algebra, determine the logical expression for outputs. C. Draw the circuit diagram of the outputs in step b.