3) Bitshift can often be confusing. This operator simply shifts all bits one direction or the other. In the case of a left shift, both signed and unsigned behave identically by padding the newly empty slot with a zero. In the case of right shift, the signed version pads the newly open MSb with a one. The unsigned version pads this bit with a zero. An example of the desired problem will be given. Example: char output=0; output=0x3F>6; i) unsigned int output=0; output=0xAF24>>8