Question: 3. Circle the compound(s) that will be completely deprotonated by NaOCH2 (in other words, reaction with NaOCH3 will lie >99% to the right). H2ONH3

3. Circle the compound(s) that will be completely deprotonated by NaOCH2

3. Circle the compound(s) that will be completely deprotonated by NaOCH2 (in other words, reaction with NaOCH3 will lie >99% to the right). H2ONH3

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