$3.$ Consider the effect that a stuck$-$at$-0($or stuck$-$at$-1)$ fault would have $($i$.$e$.,$ regardless of what the signal should be for some selector$/$enabler$,$ it remains stuck on $0($or $1))$ in the single cycle architecture depicted in slide $15$ of lecture $11,$ for following nine signals. Which of the following instruction types, if any, will not work correctly, and what do they do wrong? Consider:

$$ R$-$type $$ I$-$type $$ beq

$$ lw

$$ sw

Information provided in slides $106-127$ from Lecture $11$ might be helpful. Consider each case below separately.

$($a$)$ RegWrite$=0($b$)$ ALUOp$0=0($c$)$ ALUOp$1=1($d$)$ Branch$=1($e$)$ MemRead$=0$

$($f$)$ MemWrite$=0($g$)$ RegDest$=1($h$)$ MemToReg$=0$

$($i$)$ ALUSrc$=0$