Question: 3. Consider the system x + y + bz x+by+4z = 2 = 1 ax+ay + 2z == a In each case, determine all

3. Consider the system x + y + bz x+by+4z = 2

3. Consider the system x + y + bz x+by+4z = 2 = 1 ax+ay + 2z == a In each case, determine all values of a and b which give the indicated number of solutions, if possible. If no such a and b exist, give the reason why not. (i) no solutions (ii) exactly one solution (iii) exactly two solutions (iv) infinitely many solutions

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