Question: 3. Find the particle velocity [Ans] V(t) = s(t) = 714-4 t + 9+ + 13 t + 2 s(t)=7+4 +9 13t+2 a(t) =

3. Find the particle velocity [Ans] V(t) = s(t) = 714-4 t + 9+ + 13 t + 2 s(t)=7+4 +9 13t+2 a(t) = 3 and acceleration 4 Find the equation of a tangent and normal at x= JT 3 2 [Ans: y= 35inx-2 cosx. S(t) = - 3+ - 1+ +19. Find the velocity of the particle 5.) s(t)= Aus 2 when acceleration equal to Zero what distance Travels the particle at this time?

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