Question: 3. Line x = 2- 2 y-7 3 - x = 137 = 11 - z y = 1+3 and z=5- Located in a

3. Line x = 2- 2 y-7 3 - x = 137

3. Line x = 2- 2 y-7 3 - x = 137 = 11 - z y = 1+3 and z=5- Located in a plane, The plane passes through the points A(-2,1,0), B(1,0, -3), and C(3, -1.1). Determine the point distance P(-2,4,1) to the intersection of the a and planes

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