We use the Selfridge-Conway Method if Tara is the Trimmer and Charlotte is the Chooser. ...
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We use the Selfridge-Conway Method if Tara is the Trimmer and Charlotte is the Chooser. • Dakota Divides as above. Tara identifies Part B as the largest followed by Part A. These two parts are not worth the same to Tara, so she trims Part B: The the trimmed part B* consists of 1/3 bag of sapphires and 7/6 bags of emeralds (Parts B* and A are tied at $60,000) and so the trimming T consists of 1/6 bags of sapphires and 1/3 bags of emeralds. Complete the following table with the value of Part B* for each of the three friends. Part B 1/3 bag of sapphires, 7/6 bags of emeralds • Who choses next? . Who choses next? . Who choses next? Dakota Piece D Piece E Piece F . Who choses first? . Who choses next? . Who choses last? At the end, What part does she choose? What part does she choose? What part does she choose? . The trimming T (1/6 bags of sapphires and 1/3 bags of emeralds) is divided by into the following three pieces: Piece D consists of 2/27 bags of sapphires and 1/18 bags of emeralds Piece E consists of 5/54 bags of sapphires Piece F consists of 5/18 bags of emeralds • Complete the following table with the value of each piece for each of the three friends. Dakota Charlotte Tara Tara Dakota gets. Tara gets Charlotte gets Charlotte (Part A, B, or C) (Part A, B, or C) (Part A, B, or C) What piece of the trimming does she choose? What piece of the trimming does she choose? What piece of the trimming does she choose? bags of sapphires and bags of sapphires and bags of sapphires and (D, E, or F) (D, E, or F) (D, E, or F) bags of emeralds bags of emeralds bags of emeralds Written Assignment 2. The Selfridge-Conway Method* Suppose that three jewelers, Dakota, Tara, and Charlotte, own 3 bags of sapphires and 3 bags of emeralds worth a total of $162,000. Dakota does not have a preference for any of the stones, Tara values emeralds four times as much as sapphires, and Charlotte values sapphires three times as much as emeralds. 1. Complete the following table with the values of a bag of sapphires and a bag of emeralds for each of the three friends. Value of a bag of sapphires Value of a bag of emeralds 21,000 21,000 13,500 2. Suppose that the three jewelers are using the Selfridge-Conway Method to divide the stones. Dakota is the Divider and starts by dividing the stone into three parts as follows. . Dakota . Part A 1 bag of sapphires, 1 bag of emeralds Part A: 1 bag of sapphires and Ibag of emeralds Part B: 0.5 bags of sapphires and 1.5 bags of emeralds Part C: 1.5 bags of sapphires and 0.5 bags of emeralds Complete the following table with the values of each part for each of the three friends. Charlotte Dakota Tara 54,000 Part B 0.5 bags of sapphires, S4,000 1.5 bags of emeralds Part C 1.5 bags of sapphires, 54,000 0.5 bags of emeralds 10,800 43,200 Tara Charlotte 54,000 70, 200 37,800 40,500 54,000 40,500 67,500 We use the Selfridge-Conway Method if Tara is the Trimmer and Charlotte is the Chooser. • Dakota Divides as above. Tara identifies Part B as the largest followed by Part A. These two parts are not worth the same to Tara, so she trims Part B: The the trimmed part B* consists of 1/3 bag of sapphires and 7/6 bags of emeralds (Parts B* and A are tied at $60,000) and so the trimming T consists of 1/6 bags of sapphires and 1/3 bags of emeralds. Complete the following table with the value of Part B* for each of the three friends. Part B 1/3 bag of sapphires, 7/6 bags of emeralds • Who choses next? . Who choses next? . Who choses next? Dakota Piece D Piece E Piece F . Who choses first? . Who choses next? . Who choses last? At the end, What part does she choose? What part does she choose? What part does she choose? . The trimming T (1/6 bags of sapphires and 1/3 bags of emeralds) is divided by into the following three pieces: Piece D consists of 2/27 bags of sapphires and 1/18 bags of emeralds Piece E consists of 5/54 bags of sapphires Piece F consists of 5/18 bags of emeralds • Complete the following table with the value of each piece for each of the three friends. Dakota Charlotte Tara Tara Dakota gets. Tara gets Charlotte gets Charlotte (Part A, B, or C) (Part A, B, or C) (Part A, B, or C) What piece of the trimming does she choose? What piece of the trimming does she choose? What piece of the trimming does she choose? bags of sapphires and bags of sapphires and bags of sapphires and (D, E, or F) (D, E, or F) (D, E, or F) bags of emeralds bags of emeralds bags of emeralds Written Assignment 2. The Selfridge-Conway Method* Suppose that three jewelers, Dakota, Tara, and Charlotte, own 3 bags of sapphires and 3 bags of emeralds worth a total of $162,000. Dakota does not have a preference for any of the stones, Tara values emeralds four times as much as sapphires, and Charlotte values sapphires three times as much as emeralds. 1. Complete the following table with the values of a bag of sapphires and a bag of emeralds for each of the three friends. Value of a bag of sapphires Value of a bag of emeralds 21,000 21,000 13,500 2. Suppose that the three jewelers are using the Selfridge-Conway Method to divide the stones. Dakota is the Divider and starts by dividing the stone into three parts as follows. . Dakota . Part A 1 bag of sapphires, 1 bag of emeralds Part A: 1 bag of sapphires and Ibag of emeralds Part B: 0.5 bags of sapphires and 1.5 bags of emeralds Part C: 1.5 bags of sapphires and 0.5 bags of emeralds Complete the following table with the values of each part for each of the three friends. Charlotte Dakota Tara 54,000 Part B 0.5 bags of sapphires, S4,000 1.5 bags of emeralds Part C 1.5 bags of sapphires, 54,000 0.5 bags of emeralds 10,800 43,200 Tara Charlotte 54,000 70, 200 37,800 40,500 54,000 40,500 67,500
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Related Book For
The Legal Environment of Business
ISBN: 978-0538473996
11th Edition
Authors: Roger E Meiners, Al H. Ringleb, Frances L. Edwards
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