(33%) Problem 2: A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 286 kg. A small boy of mass m = 49 kg runs tangentially to the merry-go-round at a speed of v= 1.1 m/s, and jumps on. Randomized Variables R = 1.3 meters M = 286 kg m = 49 kg v = 1.1 m/s A 17% Part (a) Calculate the moment of inertia of the merry-go-round, in kg. m. I= sin() cos() cotan() asin() atan() acotan() cosh() tanh() Degrees Submit Hints: 0% deduction per hint. Hints remaining: 3 tan() acos() sinh() cotanh() Radians Hint 7 8 9 4 5 6 1 2 + 0 VO BACKSPACE ( ^/ ^ 1 - 3 HOME END DEL CLEAR Feedback I give up! Feedback: 0% deduction per feedback. theexpertta.com Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 4 (0% per attempt) detailed view A 17% Part (b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. A 17% Part (c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. A 17% Part (d) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry-go-round when the boy is half way between the edge and the center of the merry go round? A 17% Part (e) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy is at the center of the merry go round? A 17% Part (f) Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the ground with zero velocity with respect to the ground. What is the angular speed in radians/second of the merry-go-round after the boy jumps off?