Question: 3-6. There is a function called Si(x) = x- -2k-1 (3) (3!) (5) (5!) (7) ( 7 !) ... = 2k- 109 (- 1) k+1

3-6. There is a function called Si(x) = x- -2k-1 (3)

3-6. There is a function called Si(x) = x- -2k-1 (3) (3!) (5) (5!) (7) ( 7 !) ... = 2k- 109 (- 1) k+1 (2k-1) ((2k-1)!) 3. Find the open interval of absolute convergence

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