$4-30)$ Consider a flat$-$plate collector with the following specifications.

Collector area A $=2\mathrm{.}2$m$^2$

Heat loss Coefficient U $=2\mathrm{.}8$ W$/($m$^2)$

Flow rate of water into tubes m $\_$w$=0\mathrm{.}020$ kg$/$s

Water inlet temperature T$\_($w$,$in$)=75=348\mathrm{.}15$K

Product of transmissivity of glazing and absorptivity of the absorbed $\backslash$tau $\backslash$alpha $=0\mathrm{.}84$

The collector efficiency factor F $=0\mathrm{.}83$

Incident angle modifier is taken to be $1$

Average Hourly Data for ambient temperature and solar heat flux incident in a July day @ $40$ degrees latitude are $($Attached Photo$)$

a$)$ calculate the collector heat flux incident removal factor

b$)$ for each hour, calculate the useful heat gain, the collector efficiency, and temperature of water at the collector exit

c$)$ Calculate the total useful heat gain and the overall collector efficiency for the entire day.