$4.3\mathrm{.}98$ x $10-2$ mol of NO$2($g$)$ is placed in a $4$L container. Over time NO$2$ will react to form some N$2$O$4($g$)$: N$2$O$4($g$)<>2$NO$2($g$)$ K$=4\mathrm{.}50$ at $150$ CDetermine the equilibrium concentrations of N$2$O$4$ and NO$2$