Question: 4 . A 4 mm - diameter, 4 4 cm - long aluminum alloy rod has an electric heater wound over the central 4 cm

4. A 4 mm -diameter, 44 cm -long aluminum alloy rod has an electric heater wound over the central 4 cm length. The outside of the heater is well insulated. The two 20 cm -long exposed portions of rod are cooled by an air stream at 300 K giving an average convective heat transfer coefficient of \(50\mathrm{~W}/\mathrm{m}^{2}\mathrm{~K}\). The power input to the heater is 10 W and \( k=200\mathrm{~W}/\mathrm{m}\mathrm{K}\) for the aluminum alloy.
a [10 points]. Determine the temperature distribution along the rod, and find the temperature at the ends of the rod (at \( x=22\mathrm{~cm}\)) with neglecting thermal resistance between the heater and the aluminum alloy.
b [10 points]. Repeat Problem 4.a, but thermal resistance between the heater and the aluminum alloy is \(3\times \)\(10^{-4}\mathrm{~m}^{2}\cdot \mathrm{~K}/\mathrm{W}\). Determine the temperature distribution along the rod, and find the temperature at the ends of the \(\operatorname{rod}(\) at \( x=22\mathrm{~cm})\).
c [15 points]. Initial temperature distribution along the rod is assumed to be the temperature distribution obtained from Problem 4.b. The heater is removed, and both ends of the rods is suddenly exposed to a hot air stream at 1500 K with a convective heat transfer coefficient of \(1000\mathrm{~W}/\mathrm{m}^{2}\mathrm{~K}\). Assume all rod surfaces are adabatic except for both ends of the rods. How long will it take for the center of the rod (at \( x=0\)) to reach 1000 K ?
d [15 points]. The heater is removed, and the rod is initially at 300 K for all \( x \) values. The center of the rod (\(2\mathrm{~cm}
4 . A 4 mm - diameter, 4 4 cm - long aluminum

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