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4. A particle is moving in a straight line and its distance s, in meters, from a fixed point in the line after t seconds is given by the equation, s(t) = 12t - 15 2 + 4 13 a. Find the velocity of the particle after 3 seconds. Differentiate. b. Find the acceleration at time t = 3 Differentiate the function. 6Vx + 3x y = h(0) = 02 sin(0) 5 x2 X h'(0) = Find f' ( x ) and f" ( x ) . f(x ) = vxex f' ( x ) = f " ( x ) = Differentiate. Suppose that f(4) = 3, g(4) = 4, f'(4) - -2, and g'(4) = 5. Find h'(4). (a) h(x) = 2f(x) + 5g(x) h'(4) = 28 y = sec(0) tan(0) (b) h(x) = f(x)g(x) h' ( 4 ) = ( c ) h ( x ) = 9 ( x ) y = h' (4) = X (d) h (x ) = g(x) f(x) + g(x) h (4) =