Question: 4. Component A is converted to B in a reactor. Komponen A ditukarkan kepada B dalam sebuah reaktor. AB The reaction is to be carried

 4. Component A is converted to B in a reactor. Komponen

4. Component A is converted to B in a reactor. Komponen A ditukarkan kepada B dalam sebuah reaktor. AB The reaction is to be carried out adiabatically in the liquid phase under high pressure using trace amount of liquid catalyst which gives a specific reaction rate of 31.1h1 at 360K. With the feed entering at 330K, find the reactor volume necessary to process 163kmol/h at 40% conversion of a mixture 90mol%A and 10mol%C, which is considered an inert. Tindakbalas tersebut dijalankan secara adiabatik dalam fasa cecair di bawah tekanan tinggi dengan menggunakan amaun pemangkin cecair yang sangat kecil, yang mana memberi kadar tindakbalas spesifik 31.1 jam 1 pada 360K. Dengan suapan masuk pada suhu 330K, carikan isipadu reaktor yang diperlukan untuk memproses 163 kmoljam pada 40% penukaran bagi suatu campuran 90mol%A dan 10 mol %, yang dianggap suatu bahan lengai. [i] Develop the design equation through mol balance, and energy balance in order to calculate the CSTR volume necessary to achieve 40% conversion for the above conditions. Bangunkan persamaan rekabentuk melalui imbangan mol, dan imbangan tenaga untuk mengira isipadu CSTR yang diperlukan untuk mencapai penukaran sebanyak 40% untuk keadaan di atas. [15 marks/markah] [ii] Find the equilibrium conversion for the reaction. Carikan penukaran keseimbangan bagi tindakbalas tersebut [4 marks/markah] [iii] If a PFR is used for the reaction at 40% conversion, discuss the volume needed comparing to that of a CSTR. Jika sebuah PFR digunalan untuk tindakbalas tersebut pada penukaran 40\%, bincangkan isipadu reaktor PFR yang diperlukan berbanding dengan isipadu CSTR yang diperlukan. [6 marks/markah] Additional information: HRri=6900J/molA, Activation energy =65.7kJ/mol kA/kB=3.03 at 333K CA0=9.3kmol/m3 Specific heat capacities: CPA=CPB=141J/mol.K CPC=161J/mol.K Adiabatic energy balance: X=[HRx0(TR)+CP(TTR)]iCP1(TTi0)

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