Question: 4. Given the sets X = {24k + 7 | ke Z}, Y = {4n+3|ne Z}, Z = (6m + 1|me Z}, prove that X

4. Given the sets X = {24k + 7 | ke Z}, Y =
4. Given the sets X = {24k + 7 | ke Z}, Y = {4n+3|ne Z}, Z = (6m + 1|me Z}, prove that X CY and X C Z but Y & Z

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