Question: 4. Given the system of linear equations 2.1 - X2 + 23 = -1 8x1 - 4x2 - 23 = -4 21 - 22 =

 4. Given the system of linear equations 2.1 - X2 +

23 = -1 8x1 - 4x2 - 23 = -4 21 -

4. Given the system of linear equations 2.1 - X2 + 23 = -1 8x1 - 4x2 - 23 = -4 21 - 22 = -1 determine if a solution exists. If it does, what is the solution? A) *Let t be a variable such that t goes from negative infinity to positive infinity. The solution set is (t - 5, t, 0). B) Let t be a variable such that t goes from 0 to positive infinity. The solution set is (?t, 3t-?, t) C) Let t be a variable such that t goes from negative to positive infinity. The solution set is (t, 3t - 3, t) D) Let t be a variable such that t goes from negative to positive infinity. The solution set is( 3 t + 1, - 5t, t). E) None of the above

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