Question: 4 Let p(t) = Vt - 3 (a) p' (t) = VilVi - 32 (b) Find an equation for the line tangent to the graph

 4 Let p(t) = Vt - 3 (a) p' (t) =

4 Let p(t) = Vt - 3 (a) p' (t) = VilVi - 32 (b) Find an equation for the line tangent to the graph of y = p(t) at the point (t, y) = (28, 4/5). (x - 28) Tangent line: y = V 28( 28 - 3)2

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