40.0.0.4 Interface 7 0.0.0.5 Interface 8 Network 40.0.0.0 Network 50.0.0.0 Router B 40.0.0.3 Interface 5 0.0.0.6 Interface 1 50.0.0.7 Interface 3 Router A Router D Router C 30.0.0.1 Interface 1 0.0.0.2 Interface 2 60.0.0.8 Interface 1 Network 30.0.0.0 Network 60.0.0.0 Figure Q2 (a) Referring to the computer network in Figure Q2, based on shortest path routing, construct the routing table of Router C with the following format Network Destination Gatewa Interface 40.0.0.0 50.0.0.0 60 (8 marks) (b) Continue from question 2(a), suppose the connection between Router B and Network 50.0.0.0 is lost. Update the routing table of Router C such that all the networks in Figure Q2 are still reachable Remark: Provide the complete routing table of Router C after the update Give the subnet mask for dividing network 30.0.0.0 into 30 equal-size subnets Continue from question 2(c), provide the feasible IP address range in the 15th subnet. (2 marks) (c) (4 marks) (d) (6 marks) 40.0.0.4 Interface 7 0.0.0.5 Interface 8 Network 40.0.0.0 Network 50.0.0.0 Router B 40.0.0.3 Interface 5 0.0.0.6 Interface 1 50.0.0.7 Interface 3 Router A Router D Router C 30.0.0.1 Interface 1 0.0.0.2 Interface 2 60.0.0.8 Interface 1 Network 30.0.0.0 Network 60.0.0.0 Figure Q2 (a) Referring to the computer network in Figure Q2, based on shortest path routing, construct the routing table of Router C with the following format Network Destination Gatewa Interface 40.0.0.0 50.0.0.0 60 (8 marks) (b) Continue from question 2(a), suppose the connection between Router B and Network 50.0.0.0 is lost. Update the routing table of Router C such that all the networks in Figure Q2 are still reachable Remark: Provide the complete routing table of Router C after the update Give the subnet mask for dividing network 30.0.0.0 into 30 equal-size subnets Continue from question 2(c), provide the feasible IP address range in the 15th subnet. (2 marks) (c) (4 marks) (d) (6 marks)