Question: +42t. An object is thrown vertically upward from the surface of a celestial body at a velocity of 42 meters per second. Its distance from

+42t. An object is thrown vertically upward from the surface of a celestial body at a velocity of 42 meters per second. Its distance from the surface at t seconds is given by s(t) = -0.7 +4 a. How fast is the object moving 7 seconds after being thrown? b. How long after the object is thrown does it reach its maximum height? c. How high will the object go? a. The object's velocity after 7 seconds is m/sec. (Round to the nearest tenth as needed.) ***

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