An object is thrown vertically upward from the surface of a celestial body at a velocity of $48$ meters per second. Its distance from the surface at $t$ seconds is given by $s(t)=-0\mathrm{.}8t^{2}48t.$

$($a$)$ How fast is the object moving $5$ seconds after being thrown?

$($b$)$ How long after the object is thrown does it reach its maximum height?

$($c$)$ How high will the object go$?$

$($a$)$ The object's velocity after $5$ seconds is $\frac{m}{sec}.$

$($Round to the nearest tenth as needed.$)$