$5-(10\%)$ The allowable loop misclosure for a differential leveling construction survey with $4$

setups of the level is:

$($a$.)0\mathrm{.}012$ m

b$.0\mathrm{.}04$ m

allowable misclosure. $=\frac{0\mathrm{.}01\sqrt[\phantom{2}]{n}}{3\mathrm{.}28}$ where $x$ is number

c$.0\mathrm{.}014$ m

d$.$ None of the above.

so whow ble nistloswe $=\frac{0\mathrm{.}02\sqrt[\phantom{2}]{4}}{3\mathrm{.}28}=\frac{0\mathrm{.}04}{3\mathrm{.}28}=0\mathrm{.}0122.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,($why did we divide by $3\mathrm{.}28$ when the formula is just $0\mathrm{.}02$xradicaln, and why does dividing by $3\mathrm{.}28$ give us a correct answer and how do i know when or not to divide$)$