5. (15) Thermal dilution has been applied as step changes in power P in watts of a resistor placed in the right ventricle of volume Vh in ml. Temperature at the output of the right heart T in deg C is measured : T=37+.03*(1-exp(-t*Q/Vh)) which is based on the differential equation: w dt/dt = P/(4.18*Vh) -Q*(T-37)/Vh where 37=baseline blood temperature, t is in seconds 4 = Q=cardiac output in ml/sec, P=applied power in watts a)(5) Calculate the steady state temperature due to a step change in P=10 watts from P=0.- b) (5) Calculate Q in ml/sec c(5) If T=37.15 5 seconds after the step change in P, calculate Vh in mL as a function of Q- 5. (15) Thermal dilution has been applied as step changes in power P in watts of a resistor placed in the right ventricle of volume Vh in ml. Temperature at the output of the right heart T in deg C is measured : T=37+.03*(1-exp(-t*Q/Vh)) which is based on the differential equation: w dt/dt = P/(4.18*Vh) -Q*(T-37)/Vh where 37=baseline blood temperature, t is in seconds 4 = Q=cardiac output in ml/sec, P=applied power in watts a)(5) Calculate the steady state temperature due to a step change in P=10 watts from P=0.- b) (5) Calculate Q in ml/sec c(5) If T=37.15 5 seconds after the step change in P, calculate Vh in mL as a function of