$5\mathrm{.}21$ LAB: Adjust list by normalizing

When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This adjustment can

be done by normalizing to values between $0$ and $1,$ or throwing away outliers.

For this program, adjust the values by dividing all values by the largest value. The input begins with an integer indicating the number of

floating$-$point values that follow. Assume that the list will always contain positive floating$-$point values.

Output each floating$-$point value with two digits after the decimal point, which can be achieved by executing

cout $$ fixed $$ setprecision$(2)$; once before all other cout statements.

Ex: If the input is:

$5$

$30\mathrm{.}050\mathrm{.}010\mathrm{.}0100\mathrm{.}065\mathrm{.}0$

the output is:

$0\mathrm{.}300\mathrm{.}500\mathrm{.}101\mathrm{.}000\mathrm{.}65$

The $5$ indicates that there are five floating$-$point values in the list, namely $30\mathrm{.}0,50\mathrm{.}0,10\mathrm{.}0,100\mathrm{.}0,$ and $65\mathrm{.}0.100\mathrm{.}0$ is the largest value in the

list, so each value is divided by $100\mathrm{.}0.$

For coding simplicity, follow every output value by a space, including the last one.

$573056\mathrm{.}4560684\mathrm{.}93z9y7$

LAB

ACTIVITY

$5\mathrm{.}21\mathrm{.}1$: LAB: Adjust list by normalizing

$\frac{0}{10}$