Question: 5 2 8 0 4 0 3 4 8 9 5 2 8 . 9 3 z qy 7 Jump to level 1 The first

5280403489528.93z qy 7
Jump to level 1
The first and second integers in the input are read into variables previousNum and currentNum, respectively. Write a loop that iterates until currentNum is not equal to 8 plus previousNum. In each iteration:
Output currentNum, followed by "is 8 plus ", previousNum, and ". Sequence is increasing arithmetically." End with a newline.
Assign previousNum with currentNum.
Read the next integer from input and assign currentNum with the integer read.
After the loop, output the last integer read followed by " breaks the sequence." and a newline.
Click here for example
Note: Assume that input has at least two integers.
import java.util.Scanner;
public class Sequencing {
public static void main(String[] args){
Scanner scnr = new Scanner(
System.in);
int currentNum;
int previousNum;
previousNum = scnr. nextInt ();
currentNum = scnr. nextInt () ;
System.out.println("Sequence starts at "+ previousNum +".");
V* Your code goes here */
}
}
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 5280403489528.93z qy 7 Jump to level 1 The first and second

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