Question: ' ' '5 (5) A stretched wire vibrates in its fundamental mode at a frequency of 450 HZ. What would be the fundamental frequency if

 ' ' '5 (5) A stretched wire vibrates in its fundamentalmode at a frequency of 450 HZ. What would be the fundamental

' ' '5 (5) A stretched wire vibrates in its fundamental mode at a frequency of 450 HZ. What would be the fundamental frequency if the wire were half as long, its diameter were doubled, and its tension were decreased by a factor of two? : Tries one 0 q (6) Two identical speakers, one directly behind the other, are generating a 392 Hz sound wave. What is the smallest separation distance between the speakers that will produce destructive interference at the position of a listener standing in front of them? The speed of sound in air is 343 m/s. :] SubmitAnswer Tries 0/10 "3 (7a) When a hollow metal pipe that is open at both ends is cut into two pieces, the lowest resonance frequency in one piece is 258 HZ and that for the other is 409 HZ. What lowest resonant frequency would have been produced by the original length of pipe? Assume the speed of sound in air is 345 m/s. : Tries one (7b) How long was the original pipe? I:] SubmitAnswer Tries 0/10 0 q (8) A 102.3 g cord has an equilibrium length of 5.68 m. The cord is stretched horizontally to a length of 7.47 m, then vibrated at 28.2 Hz. This produces a standing wave with two antinodes. What is the spring constant of the cord? :] Submit Answer Tries 0/10 0 a (9a) A 134.7 cm long, 8.27 g string, fixed at both ends, oscillates in its n = 3.00 mode with a frequency of 338.0 Hz and a maximum amplitude of 4.96 mm. What is the wavelength of the oscillation? SubmitAnswer Tries 0/10 (9b) What is the tension in the string? :] SubmitAnswer Tries 0/ 10 "a Given , of = 450 Hz . we know that . f = i In where , L = length of wine . T = Tension . m = mass . to T 21 T 21 Ld 3 TI Here , d= diamerten . For fundamental frequency f 1 = ( 2 ) ( 20 ) 7/ J TT = 450 HZ = 318. 20 HZ 1. 14142

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