5) Find the maximum value of (x) f(x)=1+x on the indicated interval. [0,2] HINT: Much like...

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5) Find the maximum value of "(x) f(x)=1+x on the indicated interval. [0,2] HINT: Much like the previous question except that you are focussing only on the max. Input your function as surd((1+x^2),2); Let your second derivative function equal abs(df2); assuming that df2 is the second derivative. Substitute your endpoints 0 and 2 into your absolute value second derivative function. Find third derivative and solve it for x. Substitute the result obtain into your second derivative absolute value function. Compare all y-values obtained for maximum value. 6) Without the aid of a graph, find the absolute maximum and minimum values of the function f(x)=36x + 2665x + 240x - 675 + 4534x - 5836x3 - 516x5 over the interval [0,4] HINT: Input your function into maple, find the first derivative and solve it for x after setting it to zero. Substitute the x-values obtained as well as your endpoints into the original functions to observe the y-values. Only subs x-values that lie within the closed interval given. 5) Find the maximum value of "(x) f(x)=1+x on the indicated interval. [0,2] HINT: Much like the previous question except that you are focussing only on the max. Input your function as surd((1+x^2),2); Let your second derivative function equal abs(df2); assuming that df2 is the second derivative. Substitute your endpoints 0 and 2 into your absolute value second derivative function. Find third derivative and solve it for x. Substitute the result obtain into your second derivative absolute value function. Compare all y-values obtained for maximum value. 6) Without the aid of a graph, find the absolute maximum and minimum values of the function f(x)=36x + 2665x + 240x - 675 + 4534x - 5836x3 - 516x5 over the interval [0,4] HINT: Input your function into maple, find the first derivative and solve it for x after setting it to zero. Substitute the x-values obtained as well as your endpoints into the original functions to observe the y-values. Only subs x-values that lie within the closed interval given.