5. Liquid methanol (CH3OH) is to be burned with 100% excess air. The engineer designing the...
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5. Liquid methanol (CH3OH) is to be burned with 100% excess air. The engineer designing the furnace must calculate the highest temperature (in °C) that the furnace walls will have to withstand so that an appropriate material of construction can be chosen. Perform this calculation assuming that one mole of methanol is fed at 25°C and air enters at 100°C. Assume complete combustion of the methanol through the reaction given below. (8 pts) CH3OH (1) + 1.5 O2 (g) → CO2 (g) +2 H₂O (1) Given the following data: Compound H₂O (1) CO₂ (g) Standard AHf (kJ/mol) -285.8 -395.4 -238.6 CH3OH (1) Cp (02) 1.158-0.6076*102T+1.311*10-5 T² Cp (N2) = 0.2199 +0.5723*102T-2.871*10-5 T² Cp (CO2)= 36.11+4.233*102T-2.887*105T2 Cp (H2O)= 0.6880 +0.7604*102T-3.593*10-5 T? J/(mol*°C) J/(mol*°C) J/(mol*°C) J/(mol*°C) 5. Liquid methanol (CH3OH) is to be burned with 100% excess air. The engineer designing the furnace must calculate the highest temperature (in °C) that the furnace walls will have to withstand so that an appropriate material of construction can be chosen. Perform this calculation assuming that one mole of methanol is fed at 25°C and air enters at 100°C. Assume complete combustion of the methanol through the reaction given below. (8 pts) CH3OH (1) + 1.5 O2 (g) → CO2 (g) +2 H₂O (1) Given the following data: Compound H₂O (1) CO₂ (g) Standard AHf (kJ/mol) -285.8 -395.4 -238.6 CH3OH (1) Cp (02) 1.158-0.6076*102T+1.311*10-5 T² Cp (N2) = 0.2199 +0.5723*102T-2.871*10-5 T² Cp (CO2)= 36.11+4.233*102T-2.887*105T2 Cp (H2O)= 0.6880 +0.7604*102T-3.593*10-5 T? J/(mol*°C) J/(mol*°C) J/(mol*°C) J/(mol*°C)
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Related Book For
Elementary Principles of Chemical Processes
ISBN: 978-0471720638
3rd Edition
Authors: Richard M. Felder, Ronald W. Rousseau
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